28. A 0.50 L buffer solution is 0.20 M in HF and 0.40 M in NaF....

Question

Question

Answer 1

Answer #1

Part (a).

According to the Henderson-Hasselbulch equation:

pH = pKa + Log{(n_{conjugate base} + n_added
base)/(n_{weak acid} - n_{added base})} ('n' corresponds to moles)

i.e. pH = 3.82 + Log{(0.4*0.5 + 0.025)/(0.2*0.5 - 0.025)}

Therefore, pH = 4.3

Part (b).

According to the Henderson-Hasselbulch equation:

pH = pKa + Log{(n_{conjugate base} - n_added
acid)/(n_{weak acid} + n_{added acid})} ('n' corresponds to moles)

i.e. pH = 3.82 + Log{(0.4*0.5 - 0.05)/(0.2*0.5 + 0.05)}

Therefore, pH = 3.82

Answer 2

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