Question

2)a. A 15.00 ml sample of an unknown H2SO4 solution is titrated with a 0.30 M NaOH solution. The equivalence point is reached when 18.00 ml of NaOH solution is added. What is the concentration of the Unknown H2SO4 solution? (1st write balance equation)

Answer 1

The balance equation of titraation of H2SO4 With NaOH is as follows: H2SO4 + 2NaOH a Nagso4 + 2H2O At the equivalence point of this titration sumber of moles of NaOH = number of moes of We know Concentration = number of moles volume Day So number of moles - Concentration x volume For wooh, Concentration= 0.30M , volume=18 ml = 0.30 mol = 0.018L Se number of moles of Nady = 0.30 x 0.018 mole = 0.0054 mol From balanced equation we observed that a moles Naot react with 1 mole H2SO4 50 0.0054 moles NaOH react with 0.0027 moles the

So concentration of unknown H2S04 - number of moles of HR 504 - volume of H2804 - 0.0027 mol 27 | 15ml = 0.04527 0.015 L = 0.18 moi = 0.18 M