Question

O KINETICS AND EQUILIBRIUM Using Kf to calculate the equilibrium molarity of a complex For the aqueous [Fe(CN)614 complex K,=1.0 x 1035 at 25 °C. Suppose equal volumes of 0.0090 M Fe(N Dz) solution and 0.98 M KCN solution are mixed. Calculate the equilibrium molarity of aqueous Feion. Round your answer to 2 significant digits. | Ом x 6 ?

Answer 1

200 dus) Let, & volume of 0.009 M Fero Solution and a volume of 0.98 MKCN are mixed. 80. Total volume of mixture = x + x VA - 2x 80. after mixing the stelution , a) Malarity of fe (Non), Solution - hitital malweity xinitial Tolune final volume = 0.0094x = 000045M 2x b) Malarity of KCN SOL = 0.98XX - 6:49M Step © Copatero Compler foumation Ron, Feat (aq) + 6 CN- (aq) - [fe can) ian) 0.49 -6x +x 00u9-6n [Fe2+ kre [FeCoN).Je [CNO[Fe2+ : KF 1 so. x 0.0045 because we knace, (peltien act as limiting Reaguet. 0.0045 - 0.0045-x 0.0045-x 70

RE 141035 TOTT 0049-6x] Put x = 0.0045 [Fe2+] = 000045 1035x 10.49-6X 00004556 Co2 = 0.0045 (0046 3) 6x1035 [Fe2+] = 40 6X10-36 80 molarity of fertion in mixture o [Fe²+] = 4.6X10-30 M. Thank you, May it help you :)