Question

2. A current carrying copper rod of mass 3.4 x 102 kg and length 0.12 m is attached in a circuit to a power supply and held suspended above the ground. When an external 0.96 T magnetic field acts in an upward direction perpendicular to the copper rod, the rod shifts to the right, making an angle of 37° with its original position as shown in the diagrams below. power supply side-view of apparatus copper rod -- 1 = 0.12 m m = 3.4 x 102 kg B=0.96 T B = 0.96 T a) With reference to the right, side-view diagram, in which direction is the current flowing in the copper rod? Select one of the following choices: mark Into the page Out of the page Version 1 Page 1201 15 Page 12 of 15 Test A On-Line Course Physics 12 Module 6 Test A b) What is the magnitude of the current flowing in the copper rod?

Answer 1

a) Magnetic force must be acting right to counter tension as well as weight. Therefore direction of flow of current Into the page must be b) Fo= mg Fm = BIL For equilibrium Fr cos 37° = Fa & F sin 37° = Fm F Sin37° Ę Cos 370 Fm = Fa dan 37° BID = mg fan 39° I = mg fan 37° = e Be I 2.18 A 3•4X10-2kg X9.8ms2 fan 37° 0.965 * 0.12m