Question

EXERCISE HINTS: GETTING STARTED I I'M STUCK! Yet another bizarre baton is created by taking four identical balls, each with mass 0.260 kg, and fixing them as before except that one of the rods has a length of 1.08 m and the other has a length of 1.57 m. (a) Calculate the moment of inertia of this baton when oriented as shown in the figure. 1 kg • m² (b) Calculate the moment of inertia of this baton when oriented as shown in the figure, with the shorter rod vertical. I kg. m2 (c) Calculate the moment of inertia of this baton when oriented as shown in the figure, but with longer rod vertical. I = kg. m2 Need Help? Read It Talk to a Tutor

Answer 1

A)

Moment of inertia, I = m1r^2 + m2r^2 + m3r^2 + m4r^2

I = (0.26 x 0.54^2) + (0.26 x 0.785^2) + (0.26 x 0.54^2) + (0.26 x 0.785^2)

I = 0.47 kg m^2

B)

I = (0.26 x 0) + (0.26 x 0.785^2) + (0) + (0.26 x 0.785^2)

I = 0.32 kg m^2

C)

I = (0.26 x 0.54^2) + (0.26 x 0) + (0.26 x 0.54^2) + (0.26 x 0)

I = 0.15 kg m^2

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