Process (1).
H = 18 cal/mol.oC * {0 - (-15)} oC = 810 cal/mol
S = Cp ln(T2/T1) = 18 cal/mol.K * ln{(0+273)K/(-15+273) K} = 1.017 cal/mol.K
Process (2).
H = 1436 cal/mol
S = H/T = (1436 cal/mol)/273 K = 5.26 cal/mol.K
Process (3).
H = 8.7 cal/mol.oC * (-15 - 0) oC = -130.5 cal/mol
S = Cp ln(T2/T1) = 8.7 cal/mol.K * ln{(-15+273) K/(0+273) K} = -0.492 cal/mol.K
Now the toal H = 810 + 1436 + (-130.5) = 2115.5 cal/mol
And the toal S = 1.017 + 5.26 + (-0.492) = 5.785 cal/mol.K
UUober 1. Calculate AS, AH and AG for the foll atm). It is known that the heat of fusion of cal/mol, the heat of ca...
1. Calculate AS, AH and AG for the following spontaneous (irreversible) process (with 3.0 mol of water at 1 atm). H2O (liquid, -15 °C) → H2O (solid, -15 °C) It is known that the heat of fusion of water at 0 °C is 1436 cal/mol; the heat capacity of liquid water is 18.0 cal/mol, the heat of capacity of ice is 8.7 cal/mol. H2O (liquid, -10 °C) → H2O (liquid, 0 °C). HOC -130 HO -15 To calculate AS, AH...
1. Calculate AS, AH and AG for the following spontaneous (irreversible) process (with 3.0 mol of water at 1 atm). H2O (liquid, -15 °C) → H2O (solid, -15 °C) It is known that the heat of fusion of water at 0 °C is 1436 cal/mol; the heat capacity of liquid water is 18.0 cal/mol, the heat of capacity of ice is 8.7 cal/mol. H2O (liquid, -10 °C) → H2O (liquid, 0 °C). HO (liquid, -15°C) H.O(solid, -15°C) Process (1) Process...
LHVS SU Due by 8 AM, 30 of October 1. Calculate AS, AH and AG for the following spontaneous (irreversible) process (with 3.0 mol of water at 1 atm). H;O (liquid, -15 °C) → H2O (solid, -15 °C) It is known that the heat of fusion of water at 0 °C is 1436 cal/mol; the heat capacity of liquid water is 18.0 cal/mol, the heat of capacity of ice is 8.7 cal/mol. HO (liquid-15°C) HO -159 H2O (liquid, -10 °C)...
Part 2. (10pt) Determine AG for the above spontaneous (irreversible) process (with 3.0 mol of water at 1 atm): H2O (liquid, -15 °C) → H2O (solid, -15 °C) 2. (40pt) 2.0-mole ideal gas with molar heat capacity Cy.m - 5R/2 undergoes the following two processes, as shown in the P-V diagram on right. Process 1: A to B (A linear decreasing function) Process 2: B to C (constant pressure) Process 3: C to A (constant volume) Determine 4, W, AU,...
Part 2. (10pt) Determine AG for the above spontaneous (irreversible) process (with 3.0 mol of water at 1 atm): H2O (liquid, -15 °C) → H2O (solid, -15 °C) 2. (40pt) 2.0-mole ideal gas with molar heat capacity Cv.m = 5R/2 undergoes the following two processes, as shown in the P-V diagram on right. Process 1: A to B (A linear decreasing function) Process 2: B to C (constant pressure) Process 3: C to A (constant volume) Determine q, w, AU,...
Part 2. (10pt) Determine AG for the abov H2O (liquid, -15 °C) → HO (solid, -15 °C) he AG for the above spontaneous (irreversible) process (with 3.0 mol of water at 1 atm) 2. (40pt) 2.0-mole ideal gas with molar heat capacity Cm undergoes the following two processes e following two processes, as shown in the P-V diagram on right Process 1: A to B (A linear decreasing function) Process 2: B to C (constant pressure) Process 3: C to...
Part 2. (10pt) Determine AG for the ab H2O (liquid, -15 °C) → H2O (solid, -15 °C) CAG for the above spontaneous (irreversible) process (with 3.0 mol of water at 1 atm): 2. (40pt) 2.0-mole ideal gas with molar heat capacity Cyms undergoes the following two processes he following two processes, as shown in the P-V diagram on right. Process 1: A to B (A linear decreasing function) Process 2: B to C (constant pressure) Process 3: C to A...
Part 2. (10pt) Determine AG for the above H2O (liquid, -15 °C) → H2O (solid, -15 °C) G for the above spontaneous (irreversible) process (with 3.0 mol of water at 1 atm): 2. (40pt) 2.0-mole ideal gas with molar heat capacity Cv.m undergoes the following two processes, as sho right. owing two processes, as shown in the P-V diagram on Process 1: A to B (A linear decreasing function) Process 2: B to C (constant pressure) Process 3: C to...
Problem 7.7 The melting of sold ice to give liquid water has AH-144 kcal/ mol(+602 kJ/mol and AS -5.25 cal/mol.K) (220 J/(mol )) What is the value of AG for the melting process at the following temperatures? SC (265) Express your answer using two decimal places. 10 A4 OE? AG- kcal/mol kJ/mol Subm Beguest Answer Part B Is the melting spontaneous or nonspontaneous at -10° 283 K spontaneous nospontaneous in equilibrium Submit Neuts or nonpontaneous at 0273 )
AG°= AH-TAS AG=AGº+RTinQ where R=8.314 J/mol K 1. Calculate AGº for the following reaction at 25 °C if AH°= -1854 kJ/mol; AS°= -236 J/mol K CH-COCH3(g) + 402(g) → 3C02(g) + 3H2O(1) 2. NH.NO, dissolving in water is a spontaneous process. As it dissolves, the temperature of the solution decreases. Based on this, what must the signs (positive or negative) of AG, AH, and AS be?