Question

UUober 1. Calculate AS, AH and AG for the foll atm). It is known that the heat of fusion of cal/mol, the heat of capacity ofice is 8.7 cal/mol. H2O (liquid, -10°C) → HO (liquid, 0 °C). AG for the following spontaneous (irreversible) process (with 3.0 mol of water at HO (liquid. -IS O (solid, -15°C) at of fusion of water at 0 °C is 1436 cal/mol; the heat capacity of liquid water is 18.0 H0 quid 15 C To calculate AS, AH and AG of the above process (irreversible) process. we divide the process into 3 steps l'art 1. (40pt) Complete the following chart to find these thermodynamic quantities in cal or kcal. Show you calculation Process (1) Process (2) Process (3) Total

Answer 1

Process (1).

$\Delta$H = 18 cal/mol.^oC * {0 - (-15)} ^oC = 810 cal/mol

$\Delta$S = Cp ln(T2/T1) = 18 cal/mol.K * ln{(0+273)K/(-15+273) K} = 1.017 cal/mol.K

Process (2).

$\Delta$H = 1436 cal/mol

$\Delta$S = $\Delta$H/T = (1436 cal/mol)/273 K = 5.26 cal/mol.K

Process (3).

$\Delta$H = 8.7 cal/mol.^oC * (-15 - 0) ^oC = -130.5 cal/mol

$\Delta$S = Cp ln(T2/T1) = 8.7 cal/mol.K * ln{(-15+273) K/(0+273) K} = -0.492 cal/mol.K

Now the toal $\Delta$H = 810 + 1436 + (-130.5) = 2115.5 cal/mol

And the toal $\Delta$S = 1.017 + 5.26 + (-0.492) = 5.785 cal/mol.K