Question

(5%) Problem 6: The lead in pencils is a graphite composition with a Youngs modulus of about 1.10 N/m. AL Calculate how mu
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Area is given by

A = pi*d2/4 = pi*(0.51*10-3)2/4

A=2.043*10-7 m2

Young's Modulus is given by

FL Y =AAL

FL 3.2 x 0.063 AL= AY - (2.043 x 10-7)(1 x 109) 3.

AL = 0.987mm

Add a comment
Know the answer?
Add Answer to:
(5%) Problem 6: The "lead" in pencils is a graphite composition with a Young's modulus of about 1.10 N/m. AL Calcul...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • (14%) Problem 2: The "lead" in pencils is a graphite composition with a Young's modulus of...

    (14%) Problem 2: The "lead" in pencils is a graphite composition with a Young's modulus of about 1.10 N/m. * Calculate how much shorter (in mm) the length of the lead becomes in an automatic pencil if you tap it straight into the pencil with a force of 4.8 N. The lead is 0.55 mm in diameter and 61 mm long. Grade Summary AL = 3.391 Deductions 12% Potential 88% sin() cos t an() cotan) asin() acos() atan) acotan sinh)...

  • (205) Problem 5: Suppose a piano tuner stretches a steel piano wire 5.5 mm. The wire...

    (205) Problem 5: Suppose a piano tuner stretches a steel piano wire 5.5 mm. The wire was originally 0.775 mm in diameter, 1.29 m long, and has a Young's modulus of 2.10x10' N/m². Randomized Variables lo = 1.29 m 1=5.5 mm d=0.775 mm Calculate the force a piano tuner applies to stretch the steel piano wire in Newtons. Grade Summary Deductions Potential 100% ) 7 8 9 sin cotano cos asino t an) acos() 4 5 6 Submissions Attempts remaining:...

  • please help i dont understand. (10%) Problem 3: With the aid of a string, a gyroscope...

    please help i dont understand. (10%) Problem 3: With the aid of a string, a gyroscope is accelerated from rest to rad/s in 0.39. Randomized Variables c = 37 rad's t = 0.39 5 DA 50% Part (a) What is its angular acceleration, in radians per square seconds Grade Summary Deductions Potential 100% sino cos cotano asino atan acotan cosh tanh Degrees 11 t ano acos sinh cotanh) Radians Submissions Attempts remag per attempt detailed in Submit Hint I give...

  • (5%) Problem 8: Consider a 470 nm wavelength blue light falling on a pair of slits...

    (5%) Problem 8: Consider a 470 nm wavelength blue light falling on a pair of slits separated by 0.035 mm. A At what angle (in degrees) is the first-order maximum for the blue light? Grade Summary Deductions 0% Potential 100% sino TT ( 9 HOME 7 8 45 E 6 cotan atan cosh cos tano asino acos acotan tanh cotanh Degrees O Radians Submissions Attempts remaining: 3 (0% per attempt) letailed view sinho 12 برا + - 0 END NO...

  • (5%) Problem 9: Light of wavelength 624 nm in air undergoes constructive interference when it is...

    (5%) Problem 9: Light of wavelength 624 nm in air undergoes constructive interference when it is perpendicularly reflected from an oil spill on a plastic sheet. The refractive index of the oil is 1.22 and that of the plastic is 1.43. A What is the nonzero thickness, in nanometers of the thinnest oil film that causes such interference? 1 = Grade Summary Deductions Potential 0% 100% ( 7 8 9 HOME E 4 5 6 sin cos tano cotano asino...

  • (25%) Problem 4: A shopper standing 3.25 m from a convex security mirror sees his image...

    (25%) Problem 4: A shopper standing 3.25 m from a convex security mirror sees his image with a magnification of 0.275. 33% Part (a) What is his image distance in meters, measured from the surface of the mirror, given that the object distance is positive? d; = -0.89 d;=-0.89 Correct! 33% Part (b) What is the focal length of the mirror, in meters? f = -0.821 sino cos tan() cotan asino acos atan) acotan sinh cosh tanh) cotanh) Degrees Radians...

  • (20%) Problem 5: A frequently quoted rule of thumb in aircraft design is that wings should...

    (20%) Problem 5: A frequently quoted rule of thumb in aircraft design is that wings should produce about 1000 N of lift per square meter of wing. (The fact that a wing has a top and bottom surface does not double its area.) > A 50% Part (a) At takeoff, an aircraft travels at 67 m/s, so that the air speed relative to the bottom of the wing is 67 m/s. Given the sea level density of air to be...

  • Please show all work and rationale. (10%) Problem 7: Consider the circuit in the diagram, with...

    Please show all work and rationale. (10%) Problem 7: Consider the circuit in the diagram, with sources of emf listed below. Randomized Variables & = 27 V E = 46 V &z = 10.5 V & 4 = 43 V 3 R 200 Otheexpertta.com > A 33% Part (a) Find I in amps. 1;= Grade Summary Deductions Potential 100% 0% HOME E sin cos t an() cotano asin( acos atan acotan sinh cosh) | tanh) | cotanh) Degrees O Radians...

  • (6%) Problem ll: An object with height 0.95 cm is placed a distance 21 cm in...

    (6%) Problem ll: An object with height 0.95 cm is placed a distance 21 cm in front of a thin converging lens with focal length 6.75 cm, as shown The focal point locations are indicated by the small black circles. A 20% Part (a) Calculate and enter a value for the distance between the image and the lens given the values in problem statement. di = cm Grade Summary Deductions 0% Potential 100% п 7 8 9 HOME E TA...

  • (15%) Problem 9: Two planets are on a collision course, heading directly towards each other at...

    (15%) Problem 9: Two planets are on a collision course, heading directly towards each other at a relative speed of 0.245c. Randomized Variables y = 0.245 c u= 0.75 DA A spaceship sent from one planet approaches the second at 0.75c as seen by the second planet. What is the velocity of the ship relative to the first planet? Assume the a velocity directed away from the planet would be considered positive. Grade Summary u'c = Deductions 0% Potential 10096...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT