1. Calculate the bond energy of the CI-F bond using the following data: Cl2(g) + F2(g) → 2CIF(g) AH = -108 kJ...

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Question

Answer 1

Answer #1

1)

In reactant we have:

1 Cl-Cl bond

1 F-F bond

In product we have:

2 Cl-F bond

Use:

Delta H = BE(reactant) - BE(product)

-108 = BE(Cl-Cl) + BE(F-F) - 2*BE(Cl-F)

-108 = 239 + 159 - 2*BE(Cl-F)

2*BE(Cl-F) = 506

BE(Cl-F) = 253 KJ

Answer: 253

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Answer 2

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