Question

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3 …Exhaust gas at 550F and 750mmHg was sampled through EPA Method5 (see Figure 2). Total gas flow through the dry-gas meter was 2.785 cubic meters at 60F and 800mm Hg. During the sampling period, 1.50 grams of particles were collected, as well as 72.0 grams of water in the impingers.

a) Calculate the concentration of PM in the stack in µg/m^3 at stack conditions.

b) The average exhaust velocity is 20m/s and the inside diameter of the stack is 5 meters. What is the daily PM emission rate?

Answer 1

• For the EPA 5 method,the impinger collect is not considered to be the particulate matter.

So the concentration of the PM in the stack is = = 538.6 ug/m³

1.5 103 2.785 ug/m

• PM emission rate = ( Volumetric flow rate ) * ( Density of exhaust gas ) * ( Concentration of PM )
    = ( Velocity of gas * Area of stack ) * ( Density of exhaust gas ) * ( Concentration of PM )
  =
  PM (Velocity (concentration)kg/s Area of stack) * (RT
  
• =
  45028.97 103) 52 (20 4 -)*8.314 560,928 (538.6 10)kg/s 760
  
  = 1.2963 * 10 ^-6 kg/s
  
• PM emissions for a day =  ( 1.2963 * 10 ^-6 )* ( 86400) kg/day = 0.112 kg/day