w your work or your reasoning. How many grams of Green #3 dye (808.84 g/mol) are needed to prepare 5.00 L of a 3.08...

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Answer 1

Answer #1

Volume molarity of of dye deje solution = sool solution = 3:08*10 sm = 3.08 x 105 mol = 3.08% 10s x S.OL no. of male of dye =

Answer 2

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