Question 13 1 pts A reaction has AHºrxn = 82 kj and ASºrxn = 255j/K. Calculate above what temperature the reaction...

Question

Question

Answer 1

Answer #1

ΔHo = 82 KJ

ΔSo = 255 J/K

= 0.255 KJ/K

use:

ΔGo = ΔHo - T*ΔSo

for reaction to be spontaneous, ΔGo should be negative

that is ΔGo<0

since ΔGo = ΔHo - T*ΔSo

so, ΔHo - T*ΔSo < 0

82- T *0.255 < 0

T *0.255 > 82.0

T > 321.6 K

321.6 K = 321.6 - 273.15 oC

= 48.45 oC

Answer: 48.5 oC

Answer 2

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