A group of fun-loving people have decided to play a practical joke on one of their friends, but they can't decide which friend, Alice (A), Betty (B), or Connie (C). Their preferences are:
|
(BCA) |
(ACB) |
(CAB) |
|
10 |
4 |
5 |
Who wins the election using the Hare method? Does this violate the
Condorcet criterion?
| a. |
Betty, No |
|
| b. |
Connie, Yes |
|
| c. |
Alice, Yes |
|
| d. |
Connie, No |
|
| e. |
Betty, Yes |
Total votes = 10+4+5=19 and Total seats is 1.
Hare quota is Total votes/ (Total seats+1)+1 = 19/3=6.667
First preferences for each candidate:
A:4, B:10, C:5
Since B is over the Hare quota, B (Betty) is declared the winner
B is also the Condocert winner as it is preferred by 10 people over the remaining 9. So the Condocert criterion is not violated
Correct option is a) Betty, No
A group of fun-loving people have decided to play a practical joke on one of their friends, but they can't decide wh...