Question

Review Constants Periodic Table Part A The rearrangement of methyl isonitrile (CH3NC) to acetonitrile (CH CN) is a first-order reaction and has a rate constant of 5.11x105 s at 472 K Assume the initial concentration of CHs NC to be 3.80x10-2 M What is the half-life (in hours) of this reaction? hours to three significant figures. Express the time t1/23,77 hr You may want to reference (Pages 510 513) Section 13.6 while completing this problem. Submit Previous Answers Correct Since 0.693= kt12, dividing 0.693 by the rate constant (k) allows you to calculate the half-life. The initial result is in units of seconds because of the units for the rate constant, so the value must be converted to units of hours (using 1 hr = 3600 s) Part B the concentration of methyl isonitrile to drop to 15.5% of its initial value? How many hours will it take hours to three significant figures. Express the time VAEd hr Previous Answers Request Answer Submit X Incorrect; Try Again; 4 attempts remaining

Answer 1

time required is 10.1 hr

Fob a ISt OTdur action kr. N Conaentatian atez No e Np No> gitial Comentin K Rate Constnt ccondiny uestian, N 15.5/ No 0.155 No 5.11 xia 0.155 Na No e n o155 -5. // x5 en (o.155) 5.11 X3 36483.96 S 10. I A