Question

2. I am still working on my experiment which involves the terminal velocity of a bowling ball. I drop some bowling balls out of my private jet (which happened to be over a certain professor's house..) and found the following equation: 1 2* VT[K] Alter the equation so that it can be used to calculate the terminal velocity in miles per hour when the temperature of the atmosphere is measured in degrees Fahrenheit. Collect terms and simplify the equation such that it contains only two constants, and be sure to give the units on the remaining constants.

Answer 1

The given equation

V(m/s) = 2 * [1/T(K)]^0.5

Let us take

V' in miles/hr

We know that

1miles = 1609.34m

1hr = 3600s

T' in °F

V' ( miles/hr) = (1609.34m/3600s) V' = 0.447 V' m/s

T(K) = [T'(F) + 459.67] x 5/9

0.447 V'(miles/hr) = 2 * [1/{T'(F) + 459.67} x 5/9]^0.5

0.447 V'(miles/hr) = 2 * 1.342 [1/{T'(F) + 459.67}]^0.5

V'(miles/hr) = 6 * [1/{T'(F) + 459.67}]^0.5