Question

9 Sales Tax Receipts. The state of Texas maintains records pertaining to the economic development of corporations in the state. From the Economic Development Corporation Report, the following frequency distribution table summarizes the sales tax receipts from the state's Type 4A development corporations during a recent fiscal year. Suppose that one of these Type 4A development corporations is selected at random. Let ... A= event the receipts are less than $25,000 event the receipts are between $25,000 and $49,999 Receipts Frequency $0-24,999 $25,000-49,999 $50,000-74,999 $75,000-99.999 $100,000-199,999 $200,000-499.999 $500,000-999.999 S1,000,000 & over 25 23 B= 21 C = event the receipts are between $500,000 and $999,999 11 34 D= event the receipts are at least $1,000,000 44 event the receipts are either less than $50,000 $500,000 or at least 17 32 For 9a-9c, write answers as fractions. f 9a. Use the table and the/N rule to find P(R). Solution: P(R) = 9b. Determine P(A), P(B), P(C) and P(D). Solution: P(A) = P(B) = P(C)=_ and P(D) - 9c. Compute P (R) using the special addition rule. Hint: You must add four fractions. Solution: P(R) + For 9d-9e, use the complementation rule to find the probability that one of these Type 4A development corporations selected at random has receipts... C 9d, of at least $25000. Write the answer as both a fraction and a decimal rounded to three decimal places Solution: ge less than $500,000. Write the answer as as both a fraction and a decimal rounded to three decimal places Solution:

Answer 1

(9a)P(R)=P(less than 50000 or greater than 500000)=P(less than 50000)+greater than 500000)=97/107 (=0.4686)

(9b)P(A)=25/207(=0.1208)

P(B)=23/207 (=0.1111)

P(C)=17/207(=0.0821)

P(D)=32/207(=0.1546)

event	frequency	probability
A	25	25/207=0.1208
B	23	23/207=0.1111
C	17	17/207=0.0821
D	32	32/207=0.1546

(9c) P(R)=P(less than 50000 or greater than 500000)=P(less than 50000)+greater than 500000)=

P((0 to 24999)+(25000 to 50000)+(500000 to 999999)+(1000000 to over)=25/207+23/207+17/207+32/207=0.4686

(9d) P(at least 25000)=P(greater than 24999)=(23+21+11+34+44+17+32)/207=182/207=0.879

(9e) P(less than 500,000)=158/207=0.763

following information has been generated

	Frequency	cumulative frequency
0-24,999	25	25
25,000-49,999	23	48
50,000-74,999	21	69
75,000-99,999	11	80
100,000-199,999	34	114
200,000-499,999	44	158
500,000-999,999	17	175
1,000,000 & over	32	207