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Question 20 2 Points Consider the equilibrium below: FeO (s) + CO (g) <--> Fe (s) + CO2 (g) Kp = 0.403 at 1000.0 o...

Question 20

2 Points

Consider the equilibrium below:

FeO (s) + CO (g) <--> Fe (s) + CO2 (g) Kp = 0.403 at 1000.0 oC

If we start with 1.000 atm of CO and excess FeO at 1000.0 oC and allow the mixture to equilibrate, what will be the equilbrium partial pressure (in atm) of CO? BLANK-1 (ype in the numeric value, give your answer to 3 significant figures, do not use scientific notation)

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Answer #1

re o (s) + CO(g) - Fe(s) + CO2(g) 1.ooo antial (atm) change carmo ng tr at equilibrium (atm) (1.00-x) Ksp = con V 0.403 - x (

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