1. calculate Kp for the reaction C(s) + Co2(g) = 2Co(g
at 1300 k and 1 atm, the equilibrium mixture contains 85% co and
10.5% co2 by volume.
2. calculate the partial pressure of Co2 if Pco is changed to 10^-3
ATM.
Q1:
C(s) + CO2(g) 2CO(g)
PCO = (85/100)×1atm = 0.85atm
PCO2 = 15/100 × 1atm = 0.15atm
Kp = (PCO)2/PCO2 = (0.85)2/0.15 = 4.817
= 4.82
Q2:
PCO2 =( PCO)2/Kp = (10-3)2/4.817 = 2.076×10-7
= 2.1×10-7atm
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