We want to estimate the mean weekly earnings of students at a particular college with 95% confidence. How many students must be randomly selected so that the sample mean is within $1 of the population mean? Population standard deviation is known to be $10.
Solution :
Given that,
standard deviation = =10
Margin of error = E = 1
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
sample size = n = [Z/2* / E] 2
n = ( 1.96* 10 /1 )2
n =384.16
Sample size = n =384
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