Question
The pressure at 10 {\rm m} below the surface of the ocean is about2.00×105Pa.
Which of the following statements istrue?
The weight of a column of seawater 1{\rm m}^2 in cross section and 10 {\rm m} high is about 2.00×105\rm N.
The weight of a column of seawater 1{\rm m}^2 in cross section and 10 {\rm m} high plus the weight of a column of air with thesame cross section extending up to the top of the atmosphere isabout 2.00×105\rm N.
The weight of 1 {\rm m}^3 of seawater at 10 {\rm m} below the surface of the ocean is about2.00×105\rm N.
The density of seawater is about2.00×105 times the density of air at sealevel.
Now consider he pressure at 20 {\rm m} below the surface of the ocean.
This pressure is
twice that at a depth of 10 {\rm m}.
the same as that at a depth of 10 {\rm m}.
equal to that at a depth of 10 {\rm m}
plus the weight of a column of seawater 1 {\rm m}^2 in cross section and 10 {\rm m} high.
equal to the weight of a column of seawater 1{\rm m}^2 in cross section and 20 {\rm m} high.
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Answer #1
Concepts and reason

The concept used to solve this problem is variation of pressure with depth in a fluid.

First use relation of atmospheric pressure and static fluid pressure to calculate the total pressure

Finally use the relation between total pressure and area to calculate the force.

Fundamentals

If a fluid is within a container then the depth of an object placed in that fluid can be measured.

Expression for the weight of the object is,

W = mg

Here, W is the weight of the object, m is the mass of the object and g is the acceleration due to gravity.

Volume of the object is,

V = Ah

Here, A is the area of the object and h is the depth of fluid.

Expression for the force is,

Here, F is the force.

Expression for the static fluid pressure is,

Par

Here, Pat
stat
is the static fluid pressure.

If the container is open to the atmosphere above, the atmospheric pressure must be added to get the total pressure.

Expression for the total pressure is,

Proxe = Palm + Portal

Here, tot
is the total pressure and atm
is the atmospheric pressure.

(1)

Expression for the total pressure is,

Pio = Padom + Patal(vom)

Here, 10
is the total pressure at 10m
below the surface of the ocean.

Substitute 1.013x10 Pa
for atm
and 1.008x10Pa
for stat(10m)
.

Pro = (1.013x10 Pa)+(1.008x10 Pa)
= 2.021x10 Pa

Expression for the force is,

Here, F is the force.

Substitute 2.021x10 Pa
for 10
and 1m
for A.

2.021x10 Pa
1 m
= 2.021x10 N
2x10N

(2)

Expression for the static fluid pressure is,

Par

Consider the pressure at 20 m below the surface of the ocean. Since, the pressure at 20 m surface will be pressure at 10 m surface plus the pressure of the 10 m surface below the top 10 m surface.

Thus, this pressure must be equal to that at a depth of 10m
plus the weight of a column of seawater 1m
in cross section and 10m
high.

Ans: Part 1

The weight of a column of seawater 1m
in cross section and 10m
high plus the weight of a column of air with the same cross section extending up to the top of the atmosphere is about 2.00x10ʻN
.

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