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6. Spectroscopy. The molecular formula of an unknown organic compound is C8H1402. The IR, 1C-NMR and H-NMR spectra of this cSpectra for Question 6 IR ANENTE RI- NMR ררורץרן HSP-44-E17 13C NMR NB. all signals are single lines 20 so 40 1BC 120 140 200

6. Spectroscopy. The molecular formula of an unknown organic compound is C8H1402. The IR, 1C-NMR and 'H-NMR spectra of this compound are shown on the next page. Answer the following questions about this compound. (a) What is the unsaturation number for this compound? (b) What functional group(s) does this compound contain? Indicate the specific evidence for your conclusion. (c) What can you conclude from the number of 13C-NMR signals? (d) What can you conclude from the H-NMR signal at 2.3 ppm? (e) Draw the structure of this compound. (C3H1402)
Spectra for Question 6 IR ANENTE RI- NMR ררורץרן HSP-44-E17 13C NMR NB. all signals are single lines 20 so 40 1BC 120 140 200 160 100
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202N-H-X Unsaturation numbel (a) 2 (2x8) +o-/4-0 2 Unsatuvatim numhel = indicat estel czo stv /740 cn Jeoo-1300 tm tzco mee b

H HNMA C CH3 3.6 Pem, 3H ,Siaglet 59 Ppm, 1H, dd H He23 /Pm, 2H, Singlet 5ie ppm, 1H, dd Ppm, 6H, Singiet A Ppm,1H, dd CH3 C

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