Molar mass of H2CO3,
MM = 2*MM(H) + 1*MM(C) + 3*MM(O)
= 2*1.008 + 1*12.01 + 3*16.0
= 62.026 g/mol
mass of H2CO3 = 3.1 g
mol of H2CO3 = (mass)/(molar mass)
= 3.1/62.03
= 4.998*10^-2 mol
According to balanced equation
mol of CO2 formed = moles of H2CO3
= 4.998*10^-2 mol
Molar mass of CO2,
MM = 1*MM(C) + 2*MM(O)
= 1*12.01 + 2*16.0
= 44.01 g/mol
mass of CO2 = number of mol * molar mass
= 4.998*10^-2*44.01
= 2.20 g
Answer: 2.20 g
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