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(2) Given the data provided below, determine what value of pCO2 a solution of pure be in equilibrium with for the pH to be 5.

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Answer #1

H2CO3 is a weak acid and it's second dissociation constant is extremely small. We can consider the H+ ion concentration from the first dissociation of carbonic acid only.

H2CO3\leftrightharpoons H+ + HCO3-. K1

[H+] = √(c×K1)

pH = 5.0

pK1 = 6.35 ,. K1 = 10-6.35 = 4.4668×10-7

[H+] = 10-5.0 = 1.0×10-5 = √(c × 4.4668×10-7)

c × 4.4668×10-7 = 1.0×10-10

c = 2.2387×10-4M = aH2CO3

aH2CO3 = 10-1.5 × pCO2

pCO2 = 2.2387×10-4×101.5 = 7.08×10-3

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