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3. A candidate in next months election decides to take a poll to determine the chances of winning the election. 1180 randoml

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Answer #1

H0: p <= 0.50

Ha: p > 0.50

Sample proportion \hat{p} = 623 / 1180 = 0.5280

Test statistics

z = (\hat{p} - p) / sqrt [ p ( 1 - p) / n ]

= (0.5280 - 0.50) / sqrt ( 0.50 * 0.50 / 1180)

= 1.92

p-value = P(Z > z)

= P(Z > 1.92)

= 0.0274

Since p-value < 0.05 level , reject H0.

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