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The vapor pressure of methanol (l) is given by In P 23.593 - 3.6791 x 103/(T 31.317) where pressure is used in Pa and tempera

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The vapour presure methand () is given 3679지02 (T-31-317) mp 23.593 - we Knaw atm= .018 X10 Pa So 1.013 X10 Pa T =9 K 3.791X1

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