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5) The vapor pressure of liquid benzene is 20,170 Pa at 298.15 K, and AHvap = 30.72 kJ/mol at 1.00 atm. Calculate the normal
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Answer #1

From given we know that vapour pressure = 20, 170 Pa Temp = 298-15k Aluar = 30.72 kJ molt At normal boiling point .p=101,328pif you have any doubts about the answer please mention in the comments please do rate the answer.

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