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Sapling Learning In each reaction box, place the best reagent and conditions from the list below. The first step is correct,
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Answer #1

1) (CH3)3CO-

2) BH3 / THF

3) H2O2, NaOH, H2O

4) PBr3

Explanation: (CH3)3CO- is a strong base which gives dehydrohalogenation and produces alkene as product. Hydroboration-oxidation of alkene with BH3, THF and H2O2, NaOH, H2O produces least substituted alcohol as product. Reaction of alcohol with PBr3 produces alkyl halide as product.

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