1) (CH3)3CO-
2) BH3 / THF
3) H2O2, NaOH, H2O
4) PBr3
Explanation: (CH3)3CO- is a strong base which gives dehydrohalogenation and produces alkene as product. Hydroboration-oxidation of alkene with BH3, THF and H2O2, NaOH, H2O produces least substituted alcohol as product. Reaction of alcohol with PBr3 produces alkyl halide as product.
Sapling Learning In each reaction box, place the best reagent and conditions from the list below. The first step is...
In each reaction box, place the best reagent and conditions from the list below. tem HS (CH3)3CO H202, NaOH, H20 NaSH NaBH4 Brz BH3/THE PBr3 CH3COO- HBr H20, H2SO4
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In each reaction box, place the best reagent and conditions from the list below. Hint : The product is an epoxide, so work backwards to determine the intermediate and reagents. A peracid (such as mCPBA) is not available here, so what other method do you know to form epoxides? What reagent and starting material must be used to form this key intermediate? For the epoxide formation, consider the basicity and nucleophilicity of the base. Sapling Learning macmillan learning In each...