For the symmetry group of a tetrahedron, we have;
action | #orbit | #stab | |G| |
on edges | 6 | 2 | 12 |
It is to be noted that here its a bit tricky to find the stabilizer of an edge but since we know there are 2 elements in the stabilizer from the orbit-stabilizer theorem.
Let Tetra act on the set S of pairs of opposite edges of the tetra- hedron. What is the stabilizer of one such p...
Abstract Algebra
Exercise 4.2.3 Edges e, e of a tetrahedron T are said to be opposite if they a vertex). The 6 edges can be partitioned into a set X of three pairs of opposite edges. Prove that Gs, the group of symmetries of T, acts on X and the kernel K<G, is a normal subgroup of order 4 disjoint (that is, they do not share are a normal subgroup of Gs S (and (1) and S, of The previous...