Question

mutant (petite #3), the nuclear mutation in the segregational petite mutant will segregate in a 22 ratio. Since neutral petites lack mitochondrial DNA, all of the mitochondria in the offspring will come from the segregational petite parent. Thus, half of the offspring will be wild type and half will be mutant Part C Several isolated haploid petite mutants and wild-type cells were mated with each other on complete media to form diploid cells. The diploid cells were then starved so they would go through meiosis and form haploid spores. The spores were grown on minimal media plates that contained glycerol as the only carbon source (so no fermentation could occur). Which of the following could grow on the minimal media plus glycerol plates? Select alll that apply. crosses would be able to produce haploid spores that segregational petite x wild type segregational petite x neutral petife segregabonal pette x suppressive petite suppressive pette x wild type suppressive pebite x neutral petite neutral petite x wild type Previous Answers Submit Request Answer x Incorrect; Try Again; 3 attempts remaining Provide Feedback Next> hp Practice Problem 115 Review Three haploid yeast petite mutants were isolated one from each of the three classes of petite mutations-suppressive petites, neutral petites, and segregational petites You perform the crosses shown in this table. Progeny (haploid spores) Cross 50% petite; 50% wild type petite #1 x wild type petite #2 x wild type 100% petite petite #3 x wild type 100% wild type n fe Cca

Answer 1

Answer segragational petite cannot grow on non fermentable carbon source, so all the segregational mutant cannot grow on glycerol,

so wild type X neutral petite will give all normal haploid, also suppressive X wild type will give half normal and half petite

So answer are wild type X neutral petite and suppressive X wild type