Materials science
ANSWER: Consider the graph for a Pb-35% Sn alloy:
(a.) The alloy is hypoeutectic .
(b.) The composition of the first solid to form, Cf , during solidification:
Cf = 14% Sn
(c.) The amount and compositions of each phase at 184°C:
C = 19% Sn
C2 = 62% Sn
% = [(62 - 35)/(62 -19)]×100%
% = 63%
%2 = 37%
(d.) The amount and compositions of each phase at 182°C:
C = 19% Sn
C2 = 98% Sn
% = [(98 - 35)/(98 - 19)]×100%
% = 80%
%2 = 20%
(e.) The amount and compositions of each microconstituent at 182°C:
C = 19% Sn
C2 = 62% Sn
% = 63%
%2 = 37%
(f.) The amount and compositions of each phase at 25°C:
C = 2% Sn
C2 = 100% Sn
% = [(100 - 35)/(100 - 2)]×100%
% = 66%
%2 = 34%
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