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A titration of an unknown monoprotic acid was made with a NaOH solution of 0.0810M. As a result, the unknown monoprotic...

A titration of an unknown monoprotic acid was made with a NaOH solution of 0.0810M. As a result, the unknown monoprotic acid gave an MM = 201 g / mol, gave a Pka = 5.55 and a Ka of 3.01x10 ^ (-6). What monoprotic acid could you deduce based on the results?

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Molar mass of monoprotic acid = 201ghnol Ka = 3.01x106 Pka = 5.55 SYET LL-01-610 Based the on the given data and available li

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