Homework Answers
- Heat given out during reaction = heat absorbed by the calorimeter
thus
heat absorbed by calorimeter = mass of H2O x specific heat x rise in temperature
= [100 mlx 1g/mL] x 4.184J/g.C x[28.6-23.1]C
= 2301.2 J
If 0.645g of Mn on reaction gives -2301.2 J of heat
one mol ( 55g/mol) gives heat = 55g/mol x -2301.2 J /0.645g =196226. 35J of heat
= 196.23 kJ
OPTION A
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