Question

When 0.650 g Mn is combined with enough hydrochloric acid to make 100.0 mL of solution in a coffee-cup calorimeter, all of the Mn reacts, lowering the temperature of the solution from 29.0°C to 23.0°C. Find AHxn for the reaction as written. (Assume that the specific heat capacity of the solution is 4.18 J/g °C and the density is 1.00 g/mL.) O -212 kJ 0 -3.86 kJ -1.38 kJ O 3.86 kJ 212 kJ Submit Request Answer

Answer 1

mo Answer: Mass= Volume X density density of solution - 1.0 g/mL Volume of solution= 100ml Mass= LO glyly lool = 10og.=m. Heat capacity =(= 4.18 Ilgoc . Change in temperature = 29.0°C to 23.0% = 23%-29€ =-68 zot q mCATZ 100g x 4.18119C x 66°C) = 250.63 -25083 Reaction is Mn + 2HCl - Milla + H₂ q for 0.650g Mon - 250.67 -25083 q for Imol Mm (54.94g of Mn) = /-2506 x 54.94)] = -2119600 But this is heat change of calorimeter so heat Change of reaction =-q=-(-212 kJ) = (212 k] = omaan - 212 KJ Answer = lest option