You are doing marketing research about yogurt consumption. Based on your previous research, you feel sure that the...
help with 1-10 please!!!!
You are doing marketing research about yoqurt consumption Based on your previous research you feel sure that the population standard deviation of the number of yogurts consumed per year is 6. In other words, is known and = 6 You take a sample of 50 consumers and the sample mean is 32 yogurts consumed per year in other words. 32. You want to develop a confidence interval for the population mean) such that you are 90%...
please answer questions 7,9,10
A certain small town has a population of 5000 residents. You want to calculate a confidence interval for the average number of gallons of gas bought per month by the residents of this town. You want to be 95% confident that the true value of the population mean is within your interval, and you need to have a margin of error no higher than 10 gallons per month. Based on your previous research in similar towns,...
A certain small town has a population of 5000 residents. You want to calculate a confidence interval for the average number of gallons of gas bought per month by the residents of this town. You want to be 95% confident that the true value of the population mean is within your interval, and you need to have a margin of error no higher than 10 gallons per month. Based on your previous research in similar towns, you believe that the...
A certain small town has a population of 5000 residents. You want to calculate a confidence interval for the average number of gallons of gas bought per month by the residents of this town. You want to be 95% confident that the true value of the population mean is within your interval, and you need to have a margin of error no higher than 10 gallons per month. Based on your previous research in similar towns, you believe that the...
You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 25.5 m and 29.1 m. The sample size is given as 38 trees, and the document states that the population standard deviation is assumed to be 5.1 m. You wish to determine what confidence level was used to find this confidence interval. What was the sample mean found in the study? What...
Reming The You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 25.8 m and 28.0 m. The sample size is given as 37 trees, and the document states that the population standard deviation is assumed to be 5.5 m. You wish to determine what confidence level was used to find this confidence interval. 1. What was the sample mean...
You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 19.2 m and 23.4 m. The sample size is given as 38 trees, and the document states that the population standard deviation is assumed to be 6.2 m. You wish to determine what confidence level was used to find this confidence interval. 1. What was the sample mean found in...
You are reading an old report about tree heights in a certain area. The report states (without stating the confidence level) that the true population mean tree height lies between 24.4 m and 26.8 m. The sample size is given as 31 trees, and the document states that the population standard deviation is assumed to be 6.3 m. You wish to determine what confidence level was used to find this confidence interval. 1. What was the sample mean found in...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a random sample of 32 computers, the mean repair cost was $143 with a sample standard deviation of $35 (Section 6.2) Margin of error, E. <με. Confidence Interval: O Suppose you did some research on repair costs for computers and found that the population standard deviation, a,- $35. Use the normal distribution to construct a 95% confidence interval the population mean, u. Compare the results....
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you could include an explanation that would be appreciated!
Problem Value: 3 point(s). Problem Score: 0 %. Attempts Remaining: 3 attempts. (3 points) A news report states that the 99% confidence interval for the mean number of daily calories consumed by participants in a medical study is (1800, 1980). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 21 observations. Calculate the sample mean,...