Given that the heat of fusion of ice at 0o C = 334 J/g
i.e 334 joules of heat is required for the fusion of 1 gm of ice.
For 28 gms of ice, the amount of heat absorbed is 334*28 = 9352 joules = 9.35 KJ
The amount of heat absorbed to melt all of the ice at 0o C = 9.35 KJ
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