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QUESTION 15 Consider the following electron configurations for neutral atoms: I 1s22522p6352 II - 1522522p63523p4 III-1s22s22
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Answer #1

ionisation energy is the energy required to remove one electron from an element

electronic configuration of atoms

Atom 1 - 1s2 2s2 2p6 3s2

Atom 2 - 1s2 2s2 2p6 3s2 3p4

Atom 3 - 1s2 2s2 2p6 3s2 3p6

elements configuration after removal of one electron( after first ionisation energy)

Atom 1 - 1s2 2s2 2p6 3s1

Atom 2 - 1s2 2s2 2p6 3s2 3p3

Atom 3 - 1s2 2s2 2p6 3s2 3p5

elements configuration after removal of one electron( after second ionisation energy)

Atom 1 - 1s2 2s2 2p6

Atom 2 - 1s2 2s2 2p6 3s2 3p2

Atom 3 - 1s2 2s2 2p6 3s2 3p4

now in Third ionisation energy,

From above configuration,for

Atom 1 - electron will be taken out from a fully filled p orbital

Atom 2- electron will be taken out from a incompletely filled p orbital

Atom 3- electron will be taken out from a incompletely filled p orbital

So,less energy is required to take out electron from partially filled orbitals than a fully filled orbitals as half filled and fully filled orbitals are stable

therefore Atom 1 will have highest third ionisation energy

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