Question

(20 pts) You place 150 mL of water at 40 C in the refrigerator. How much energy does the refrigerator remove from the water to make ice at 00C? (Note 1: 1 mL H20 = 1 cm=1g. Note 2 See Table 4.4 in your text, along with the subsequent example.)

Answer 1

We know that change in the Heat

$\Delta Q=ms(T-T_{1})+mL$ ..1

Here m=150ml=150 cm³=150 g , s=4.186 J/g^oC , T =40^oC , T₁ =0 _, L=334 J/g

Put these value in equation 1

$\Delta Q=150*4.186*(40-0)+150*334$

$\Delta Q=75216 J$ Answer

also verify s and L value from your table .