Question

6. (20 pts) You have a beaker containing 100 mL of water. The initial temperature of the water is 20°C. (Note: Onc ml = 1 cm'). 2. You place a piece of copper into the beakct containing. When you do, the water level increases to 110.5 m... What is the mass of the copper in grams? b. If the temperature of the water increases to 35°C, how much heat (in calories) did the copper add to the water? c. You now add a piece of iron to the same beaker with the copper and the water level increases from 110.5 ml. to 113 ml. What is the mass of the iron in grams? d. Upon being added to the water, the temperature of the iron drops by 300C. How much heat in total (iron and copper) was added to the water?

Answer 1

Initial vallume of water = 100 mL Final volume after celding cooper = 110.5 ml So cooper volume = 110.5-100 = 10.5 mL or 10.5 cm? density of copper = 8.96g / m3 mass of copper 8.968 10.5 gm = [94.08 gm] o = Mew at Q = 60.lvg) x 1000 calling * (35-40) o= [15ool cal Similarly Vison = 113 – 110.5 = 2.5 mL or 2.5 cm3 Pirona 7.874 g / cm3 mass of iron = 7.874 + 2.5=(19.685 gm1 now plect loss by Irona meron AT 2 14.685 x0.17 x 30g = 649.605 cal Total Heat - 1500 + 649.605. [2149.6055 cal (a)