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38) If you were to completely burn this chocolate and transfer 100% of the heat to a 1000 ml beaker of water 20 degrees C, wh

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Answer #1

here heat Q=50 calories =4.18*50=209 Joules.209 joules is completely transfered to water

mass of water m=volume*density=1000 ml*1g/ml =1000g

heat capacity of water c=4.18J/g

Q=mc(t2-t1)

t1=200C

t2=?

209J=1000g*4.18J/g *(t2-t1)

(t2-t1) =209J/(1000g*4.18J/g)=0.050C

t2=0.05+200C=20.050C

final temperature=20.050C

thank you

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