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8. You have a large insulated container of water at 20°C. You place a 0.5kg 100°C piece of lead (specific heat 0.031cal/g.K)

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Answer #1

As the equilibrium temperature is 20 degree celcius,the water is neither loosing heat nor gaining.

So we can write,

Heat loss by Lead = heat gain by copper

m Lead Lead&T = m copper Scopper AT

(0.5 Kg)*(0.031cal/g.K)*(100–20)K = (m.copper) *(0.092cal/gK)* 20 – 0K

m Copper = 0.674Kg

please upvote...thank u:)

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