What is the theoretical yield of the below reaction: 
Homework Answers
Number of moles of hydroquinone = 1.59g/110.11g/mol = 0.01444mol
Number of moles of terephthaloyl chloride = 1.01g/203.02g/mol = 0.004975mol
The number of moles of polymer formed = 0.004975 mol
Mass of polymer formed (theoretical yield) = 0.004975mol× 327.39g/mol = 1.6287g = 1.63 g. (Answer)
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What is the theoretical yield of the below reaction: Theoretical Yield: Hydroquinone Terephthaloyl Polymer Product Chlo...
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What is the theoretical yield of polyester from the below
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2. Room temperature method using phenolphthalein Dissolve phenolphthalein (0.005 mole, 1.59 g), solid sodium hydroxide (0.4 g) and tetraethylammonium chloride (TEA) (0.5 g) in 50 mL of deionised water in a 200 ml beaker, then add a magnetic stirrer bar. Add 35mL of dichloromethane to the beaker. Cover the top of the beaker with aluminium foil. Set up a magnetic stirrer to provide continuous stirring at an intermediate speed....
Show how to determine the theoretical yield of 3.18g of Phenolphthalein combined with 2.03g of terephthaloyl...
Show how to determine the theoretical yield of 3.18g of
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form a polyester via the following equation (2 molecules of HCl are
also made in the reaction):
cl Terephtaloyl chloride Phenolphthalein poly (3-oxo-1 (3H)- Isobenzoluranylidene) 14-phenylenexy carbonyl-1,4-phenya lenecarbonyloxy - 1,4 phenylene
In the combustion of ethanol according to the UNBALANCED reaction below, find the theoretical yield of...
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In the combustion of ethanol according to the UNBALANCED reaction below, find the theoretical yield of...
In the combustion of ethanol according to the UNBALANCED reaction below, find the theoretical yield of CO2 in grams if we begin with 1000g of C2H5OH C2H5OH(I) + O2(g) --> CO2(g) + H2O(1) give your answer to 2 decimal places Useful information: H= 1.01 g/mol C = 12.01 g/mol O = 16.00 g/mol hint: balance the reaction first! 1 pts
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What is the theoretical yield of polyester from the below
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2. Room temperature method using phenolphthalein Dissolve phenolphthalein (0.005 mole, 1.59 g), solid sodium hydroxide (0.4 g) and tetraethylammonium chloride (TEA) (0.5 g) in 50 mL of deionised water in a 200 ml beaker, then add a magnetic stirrer bar. Add 35mL of dichloromethane to the beaker. Cover the top of the beaker with aluminium foil. Set up a magnetic stirrer to provide continuous stirring at an intermediate speed....
Show how to determine the theoretical yield of 3.18g of
Phenolphthalein combined with 2.03g of terephthaloyl chloride to
form a polyester via the following equation (2 molecules of HCl are
also made in the reaction):
cl Terephtaloyl chloride Phenolphthalein poly (3-oxo-1 (3H)- Isobenzoluranylidene) 14-phenylenexy carbonyl-1,4-phenya lenecarbonyloxy - 1,4 phenylene
In the combustion of ethanol according to the UNBALANCED reaction below, find the theoretical yield of CO2 in grams if we begin with 100g of C2H5OH C2H5OH(1) + O2(g) --> CO2(g) + H2O(1) give your answer to 2 decimal places Useful information: H = 1.01 g/mol C = 12.01 g/mol O = 16.00 g/mol hint: balance the reaction first!
In the combustion of ethanol according to the UNBALANCED reaction below, find the theoretical yield of CO2 in grams if we begin with 1000g of C2H5OH C2H5OH(I) + O2(g) --> CO2(g) + H2O(1) give your answer to 2 decimal places Useful information: H= 1.01 g/mol C = 12.01 g/mol O = 16.00 g/mol hint: balance the reaction first! 1 pts
Q6. 2/2 points
(a)What are the chemical formulas for the compounds below ?
Are the compounds shown
below isomers?
(b) Consider the two alkene compounds below? Which one is cis,
which one is trans?
Q7. 3/3/3 points
(a) What are addition polymerization steps?
(b) What type of polymerization does the below reaction
present?
(c) Calculate the degree of polymerization if 6,6-nylon has a
molecular weight of 120,000 g/mol, two repeating unit of Nylon6,6
shown in (b).
Q8. 4 points...
Draw an arrow pushing mechanism and find the theoretical yield
for the Grignard reaction below using the following amounts of
reagent with the given molecular weights:
565 microliters of 2-bromopropane (molecular weight =
123g/mol)
304 microliters of 4-methoxybenzaldehyde (molecular weight =
136.15g/mol)
molecular weight of product = 180.27g/mol
The
limiting reagent is _____________.
In this experiment, you will prepare the Grignard reagent isopropyl-magnesium bromide from 2-bromopropane. You will allow this Grignard reagent to react with 4-methoxy-benzaldehyde to form a secondary...
Suppose the theoretical yield in a reaction is 11.8 g and the percent yield is 58.2 %. What is the 36. actual yield of product obtained? A) 687 g B) 6.87 g C) 20.3 g D) 0.203 g Consider the oxidation of sodium metal to sodium oxide described by the balanced equation: 37. 4 Na+ O2 2 Na:O. What is the theoretical vield of Na:O in grams from 9.0 mol of O? 210 g of Na;O 18 g of Na...
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