Question

Using expressions 2.29a and 2.29b from the textbook, plot normal stress (σθ) and shear stress (τθ) versus angle of an inclined stress element for a bar loaded by axial forces. Use Matlab or Excel. What are slip bands? Why slip bands occur when mild steel bars are loaded in tension. Explain your answer using the plotted graphs.

results in the following expressions for the normal and shear stresses: (2-29a) (1 2 cos 20) (sin 20) 2 (2-29b) O sin 0 cos 0

Using expressions 2.29a and 2.29b from textbook, plot normal stress (oe) and shear stress (te) angle of an inclined stress el

results in the following expressions for the normal and shear stresses: (2-29a) (1 2 cos 20) (sin 20) 2 (2-29b) O sin 0 cos 0 T x on an inclined section oriented at an These equations give the stresses acting angle 0 to the x It is important to recognize that Eqs. (2-29a and b) statics, and therefore they tions are valid for any material, whether it behaves linearly elastically or inelastically axis (Fig. 2-55). were derived only from independent of the material. Thus, these equa- are nonlinearly, or
Using expressions 2.29a and 2.29b from textbook, plot normal stress (oe) and shear stress (te) angle of an inclined stress element for a bar loaded by axial forces. Use Matlab or Excel versus What are slip bands? Why slip bands occur when mild steel bars are loaded in tension. Explain your answer using the plotted graphs
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Answer #1

to draw the graph first we have to understand the question calculation that what the question want to ask lets start the the work with given data..

Given data:

as there is an stress element which is loaded by only axial force due to witch stress are developed,are different in different inclined plane.

figure 1

tijuaa 0 Stzess elemer arid ferce Y P

as per given equation we calculate the few data to plot the graph which is shown in excel sheet.

before drawing the graph first we have to consider some data such as dimension of stress element and amount of axial force from this we calculate the normal stress acting on the plane or for simplicity we can direct assume the amount of normal stress direct as showen in figure

figure 2

- 50 N/mm Considen dimensin (lengih, sdth hakhtand ameunt ob axial prce dhe ce we Calculate esS tarce CADSS-Secticr JD Cue diexpression CHexe negative gn in shear strest fndicate cmectom o shear storess an Pnabined plane is opposite

Graph between normal stress and inclined angle thita.

A F G H J K 2 inclined angle Normal stress Normal stress vs inclined angle 50 48.49231 4 10 Normal stress 5 20 44.15111 60 30

Graph between shear stress and inclined angle thita.

A D H K J graph data 2 inclined angle shear stress shear stress vs inclined angle 0 3 8.5505 4 10 shear stress 16.06969 20 5

Slip band are commonly known as plastic deformation which is generaly occure in low carbon containig matel like mild steel, aluminium during tension test.

during tensile test on mild steel after crossing elatic limit (point B) we come to an point name upper yield point (point C) at that point carbon atom which are present in mild steel in low concentrate, start to move or they get sliped to void which is present in mild steel due to presence of carbon atom. and this cause sudden decrease in strength which ultimately indicate plastic deformation so slip band are also known as plastic deformation(region CD in graph).

graph

OTOS. f f Neasing Soaun platuu hardning sotring Agion yield sts ain gion Strain ( 25-30 (0-12 0.12 0l.u CL 0

in the graph

HTS means high tensile steel or carbon atom concentration is more in this.

reason behind this is only presence of carbon which which is an impurity for this and it create some void in it.

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