Previously, an organization reported that teenagers spent 4.5 hours per week, onaverage, on the phone. The organization...

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Previously, an organization reported that teenagers spent 4.5 hours per week, onaverage, on the phone. The organization...

Previously, an organization reported that teenagers spent 4.5 hours per week, onaverage, on the phone. The organization thinks that, currently, the mean isgreater than 4.5. Ten randomly chosen teenagers were asked how many hoursper week they spend on the phone. The level of significance is 0.05.

The sample of teenagers’ time is: 3.0, 4.25, 5.5, 3.5, 7.0, 6.3, 2.0, 4.5, 3.7, 3.6, 7.2, 7.9

Population mean:

Sample mean:

Sample standard of deviation:

Level of significance:

Sample size:

null hypothesis (Ho):

alternative hypothesis (Ha):

Test Statistics:

P-value

What is the conclusion when you compare the p-value and the level of significance (alpha)?

What is the conclusion based on the original claim?

math Statistics-And-Probability

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Answer 1

Answer #1

Population mean = 4.5
Sample mean = 4.8708
sample std.dev = 1.8757
The level of significance is 0.05.

Sample size = 12

Below are the null and alternative Hypothesis,
Null Hypothesis: μ = 4.5
Alternative Hypothesis: μ > 4.5

Test statistic,
t = (xbar - mu)/(s/sqrt(n))
t = (4.8708 - 4.5)/(1.8757/sqrt(12))
t = 0.685

P-value Approach
P-value = 0.2538

As P-value >= 0.05, fail to reject null hypothesis.

There is not sufficient evidence to support the claim that the mean isgreater than 4.5.

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Answer 2

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