Previously, an organization reported that teenagers spent 4.5 hours per week, onaverage, on the phone. The organization...

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Previously, an organization reported that teenagers spent 4.5 hours per week, onaverage, on the phone. The organization...

Previously, an organization reported that teenagers spent 4.5 hours per week, onaverage, on the phone. The organization thinks that, currently, the mean is 4.5.Ten randomly chosen teenagers were asked how many hours per week theyspend on the phone. The level of significance is 0.05.

The sample of teenagers’ time is: 3.0, 4.25, 5.5, 3.5, 7.0, 6.3, 2.0, 4.5, 3.7, 3.6

Population mean:

Sample mean:

Sample standard deviation:

Level of significance:

Sample size:

Alternative hypothesis: (Ha)

Test statistics:

P-value:

What is the conclusion when you compare the p-value and the level of significance (alpha)?

What is the conclusion based on the original claim?

math Statistics-And-Probability

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Answer 1

Answer #1

POpulation mena = 4.5
Sample mean = 4.3350
sample std.dev = 1.5359

The level of significance is 0.05.

sample size =10

Null Hypothesis: μ = 4.5
Alternative Hypothesis: μ ≠ 4.5

Test statistic,
t = (xbar - mu)/(s/sqrt(n))
t = (4.335 - 4.5)/(1.5539/sqrt(10))
t = -0.336

P-value Approach
P-value = 0.7446

As P-value >= 0.05, fail to reject null hypothesis.

There is not sufficient evidence that, currently, the mean is 4.5

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Answer 2

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