Question

16. Order the following functions from lowest to highest 0-class. fs= 4n /n+2n2 - fonlg (n)-lg (n3) f2- 3n -lg (lg (n)) + n

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Answer #1

31459+lg(n)= O(lgn), since lg(n) will have higher growth than const value

0.5 f2 3n-lg(lg(n))+n=0(n), since n will have higher growth than lower n power and log functions 7

f3 4nn2n2/8-1.5n 0(nn)

f41.2 -0.8 2n2 0(1.2)

The growth rate of exponential increasing function is faster than polynomial functions

f53n-2n24n 5 0(n)

The highest order function polynomial is n^3 in this case

f=nlg(n)-lg(n) 4nlg(n) 31g(n) = 0(nlgn)

Now, the order will be

35

Note - Post any doubts/queries in comments section.

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16. Order the following functions from lowest to highest 0-class. fs= 4n /n+2n2 - fonlg (n')-lg (n'3) f2- 3n -l...
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