QUESTION #1 What is the pH of a buffer by mixing 1.00L of 0.020M benzoic acid, HC,H,O2, with 3.00L of 0.060M sodiu...

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Answer 1

Answer #1

Given mixture is an example for acidic buffer,

pH=pka+log(moles of salt/moles of acid)

Addition of strong acid reacts with acidic buffer , salt reacts with added acid to form acid

NaC7H5O2 +HA <--> HC7H5O2 + NaA

Added base reacts with acid and forms salt

HC7H5O2 + NaOH <-----> NaC7H5O2 +H2O

pKa=-logka=-log(6.3x10^-5)= 4.20

pH= 4.20+log(0.06x3/0.02x1)

=4.2+log(0.18/0.02)

=4.2+log(9)

=4.2+0.95

pH= 5.15

Answer 2

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