Question

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Question 5-6 Marks A motor runs a pump via a system as shown below. Determine the following The maximum power if one V-belt is used a) The maximum power if 2 V-belts identical to the V-belt in a) are used b) The maximum power if one V-belt with twice the cross sectional area as in a) is used c) Mots The conditions of the system are as follows: Pulley radius = 120 mm =160° f = 180 = 0.20 Maximum belt tension = 1250N Belt unit weight = 1.75 N/m Pulley Speed = 3500 rpm

Answer 1

SolLution- =120 mm. Given sdata p = 160 = DX09T f = 0.20 TE12s0 N m LIS Kg|m V =- 3500 2pm for Maaumem Pauen tansnntcol bj V-vert Y the helt, tqoorA 4-8.38 m1S 12= 12sa 3m 3 xo.178 caatntugaltemsian Te T=T- 416.67 theut We Knou 2,3 lagfJ f cosec 2.3 log (3 o.2 0 2.792 xCOsec 18°=1,80 6.103 T2 833 33 N T=T-T =1250-4-16.6 36..54 N NOS ol'9

Maximien fouesr tacsmid.es! = C&33.33 - 136,5 4) X 4-.138 33.71. V-belt idomticed use ol if 2 2 Pacden tsmited, P= 2x ( E 2 X337 - 42 ku V-belt cosith twice Cmoss - Best Pen Lemit m'= 2x0.1 =0.356 K9lm m Aealemgthclens so mhecome dolcble Manim0 +ensiem em beet beconme T: Mca Stoessx ahoe double, 2T = 2x1250 = 2S00 N _Nou 1 4-8.38 mLS 3 m 3mi

333.34 N Ctno temsian, Tez T 2500 but 603 emain_Sqme. TE T-T= 2500-633.34 1666.66 N 999991 2 3 089 6.103 6. (o 3 Nou Mceamem Pawer trasmatte P= C-T2 C1666.66-213089) 48.38 -67.42 R18