This question is based on linear programming concept.
It is given that to produce a shirt, i.e. output X, requires 1 hour of cutting and 5 hours of sewing.
Similarly, output y(coat) requires 4 hour of cutting and 3 hours of sewing.
Total available inputs, i.e. hour of cutting and hour of sewing are 28 and 55 respectively.
Producer makes a profit of Rs.26 on each unit of X and Rs.57 on each unit of y.
This can be better understood by presenting the given information in tabular form:
Input | product x(shirt) | product y (coat) | total inputs available |
Labour of cutting | 4 | 4 | 28 |
Labour of sewing | 5 | 3 | 55 |
Profit | 26 | 57 |
It is also given that maximum number of coats can be produced is two more than number of shirts, i.e. y= X+2.
According to question, we have to maximize profit:
Maximise Profit: P= 26x + 57y
Subject to a) 4x +4y=28 i.e. x+y =7
or 5x + 3y= 55
b) y=X+2
By solving equations: x+y=7 & y=x+2, we get X=2.5 & y = 4.5
Similarly, solve 5x+3y=55 & y=X+2, we get X= 6.12 & y = 8.12
To maximize the profit, we have to solve the equations x+y= 7 & 5x+ 3y=55, we get X=12 & y=14.
By substituting all the values of x & y in profit function, we can check, when the profit is get maximised.
P= 26x + 57y
At ( x=2.5, y=4.5) P = 26(2.5) + 57(4.5)= 321.5
At (X=6.12, y=8.12) P= 26(6.12)+57(8.12) = 621.96
At (X=12, y= 14) P= 26(12)+57(14)= 1110
A producer earns a maximum profit =1110 by producing 12 shirts and 14 coats.
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