Question 4
a) Solve y```` -4y```-5y``+36Y`− 36
Solve the following DE y(4) + 5y" + 4y = sin x + cos2x
Solve the following DE y (4) + 5y"' + 4y = sin x + cos2x Good Luck
Question 5 < > Given the differential equation y' + 5y' + 4y = 0, y(0) = 2, y'(0) = 1 Apply the Laplace Transform and solve for Y(8) = L{y} Y(s) = Now solve the IVP by using the inverse Laplace Transform y(t) = L-'{Y(s)} g(t) =
1. Solve the equation y" + 4y' + 5y = 0 with the initial conditions y(0) = /2, y'(0) = -5.
6. (17 pts) Solve y' + 5y' + 4y = 1- u. (), y(0) = 0, y'(0)=0. What happens to the solution as to
Given the differential equation y"' + 5y' – 4y = 4 sin(3t), y(0) = 2, y'(0) = -1 Apply the Laplace Transform and solve for Y(s) = L{y} Y(s) = 1
Given the differential equation y” + 5y' – 4y = 4 sin(3t), y(0) = 2, y'(0) = -1 Apply the Laplace Transform and solve for Y(s) = L{y} Y(s) = (293 +52 + 188 +21) (52 +58 - 4)( 92 +9)
17. Use the Laplace transform to solve the initial value problem: y" + 4y' + 4y = 2e-, y(0) = 1, (O) = 3. 18. Use the Laplace transform to solve the initial value problem: 4y" – 4y + 5y = 4 sin(t) – 4 cos(1), y(0) = 0, y(0) = 11/17.
Solve the given initial value problem. y'' - y'' – 36y' + 36y = 0 y(0) = -5, y'(0) = 49, y''(0) = - 215 y(x) =
The general solution of y(1) – 5y" – 36y = 0) is: (a) y = Cicos 3x + C2 sin 3x + C3e2x + C4e-20 (b) y=Ci cos 3x + C2 sin 3x + C3 cos 2x + C4 sin 2.0 (e) y=Cicos 2x + C2 sin 2x + C3e3x + Cae-31 (d) y=Cicos 2x + C2 sin 2x + C3e3x + Caxe3r (e) None of the above.