Question

(25%) Problem 2: Fiber optics are an important part of our modern internet. In these fibers, two different glasses are used to confine the light by total internal reflection at the critical angle for the interface between the core (ncore = 1.491) and the cladding (neladding = 1.465). n cladding n core Otheexpertta.com A 50% Part (a) Numerically, what is the largest angle (in degrees) a ray will make with respect to the interface of the fiber 0max» and still experience total internal reflection? Grade Summary Deductions өтaх 3D 0%

Answer 1

Snell's Law : n₁(sin(i))=n₂(sin(r))

where n1 = refractive index of first medium or incident medium --> here n_core = 1.491

           n2 = refractive index of the second medium or refractive medium --> here n_cladding = 1.465

           i = incident angle

           r = refractive angle

for total internal reflection, at critical angle , refractive angle (r) = 90 degrees

(n2)arer Sint0 n2 SinGe= () danser Sinecn Өет Sint But the Quushiom was asked to ind out, पं e efec 9o ule need to tind this ange

Sint.y65 .491 ec 79.28 90-0e 7o-71.28 10.72 mar 10.72 (eman is obtained at only. Crifital ange

fart b)femam 5 -Ondi# Omont ec9o 98 2 90- emor e85 ee Sin Cladding n Cove ndadding Sin 850 ncore Sin 85 ncove . ndadding O916 X .41 t.485