Question

How many mL of a 0.137 M aqueous solution of barium sulfide, Bas, must be taken to obtain 8.80 grams of the salt? mL

Answer 1

Number of moles = amount in g / molar mass

Number of moles = 8.80 grams / 169.39 g/mol

=0.052 moles

We know that molarity = number of moles / volumes in L

Here number of moles =0.052 moles

Molarity = 0.137 M or moles / L

Volume in L= 0.052 moles /0.137 mole/ L

= 0..380 L

= 0.380 L*1000 ml/1 L

= 380 ml